2(4-2n)=-2(n+5)

Solution for 2(4-2n)=-2(n+5) equation:

2(4-2n)=-2(n+5)

We move all terms to the left:

2(4-2n)-(-2(n+5))=0

We add all the numbers together, and all the variables

2(-2n+4)-(-2(n+5))=0

We multiply parentheses

-4n-(-2(n+5))+8=0


We calculate terms in parentheses: -(-2(n+5)), so:

-2(n+5)

We multiply parentheses

-2n-10

Back to the equation:

-(-2n-10)


We get rid of parentheses

-4n+2n+10+8=0

We add all the numbers together, and all the variables

-2n+18=0

We move all terms containing n to the left, all other terms to the right

-2n=-18

n=-18/-2

n=+9