(11x+2)x=160

Solution for (11x+2)x=160 equation:

(11x+2)x=160

We move all terms to the left:

(11x+2)x-(160)=0

We multiply parentheses

11x^2+2x-160=0

a = 11; b = 2; c = -160;
Δ = b2-4ac
Δ = 22-4·11·(-160)
Δ = 7044
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{7044}=\sqrt{4*1761}=\sqrt{4}*\sqrt{1761}=2\sqrt{1761}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{1761}}{2*11}=\frac{-2-2\sqrt{1761}}{22}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{1761}}{2*11}=\frac{-2+2\sqrt{1761}}{22}
$