3k-4=3(1-2k)

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Solution for 3k-4=3(1-2k) equation: 



3k-4=3(1-2k)

We move all terms to the left:

3k-4-(3(1-2k))=0

We add all the numbers together, and all the variables

3k-(3(-2k+1))-4=0



We calculate terms in parentheses: -(3(-2k+1)), so:

3(-2k+1)

We multiply parentheses

-6k+3

Back to the equation:

-(-6k+3)



We get rid of parentheses

3k+6k-3-4=0

We add all the numbers together, and all the variables

9k-7=0

We move all terms containing k to the left, all other terms to the right

9k=7

k=7/9

k=7/9

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