2(4+4x)=7(x-2)

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Solution for 2(4+4x)=7(x-2) equation: 



2(4+4x)=7(x-2)

We move all terms to the left:

2(4+4x)-(7(x-2))=0

We add all the numbers together, and all the variables

2(4x+4)-(7(x-2))=0

We multiply parentheses

8x-(7(x-2))+8=0



We calculate terms in parentheses: -(7(x-2)), so:

7(x-2)

We multiply parentheses

7x-14

Back to the equation:

-(7x-14)



We get rid of parentheses

8x-7x+14+8=0

We add all the numbers together, and all the variables

x+22=0

We move all terms containing x to the left, all other terms to the right

x=-22

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