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4r-14=9/4r
We move all terms to the left:
4r-14-(9/4r)=0
Domain of the equation: 4r)!=0We add all the numbers together, and all the variables
r!=0/1
r!=0
r∈R
4r-(+9/4r)-14=0
We get rid of parentheses
4r-9/4r-14=0
We multiply all the terms by the denominator
4r*4r-14*4r-9=0
Wy multiply elements
16r^2-56r-9=0
a = 16; b = -56; c = -9;
Δ = b2-4ac
Δ = -562-4·16·(-9)
Δ = 3712
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3712}=\sqrt{64*58}=\sqrt{64}*\sqrt{58}=8\sqrt{58}$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-56)-8\sqrt{58}}{2*16}=\frac{56-8\sqrt{58}}{32} $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-56)+8\sqrt{58}}{2*16}=\frac{56+8\sqrt{58}}{32} $
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