2(4+3x)=(9x-2)-(x-4)

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Solution for 2(4+3x)=(9x-2)-(x-4) equation: 



2(4+3x)=(9x-2)-(x-4)

We move all terms to the left:

2(4+3x)-((9x-2)-(x-4))=0

We add all the numbers together, and all the variables

2(3x+4)-((9x-2)-(x-4))=0

We multiply parentheses

6x-((9x-2)-(x-4))+8=0



We calculate terms in parentheses: -((9x-2)-(x-4)), so:

(9x-2)-(x-4)

We get rid of parentheses

9x-x-2+4

We add all the numbers together, and all the variables

8x+2

Back to the equation:

-(8x+2)



We get rid of parentheses

6x-8x-2+8=0

We add all the numbers together, and all the variables

-2x+6=0

We move all terms containing x to the left, all other terms to the right

-2x=-6

x=-6/-2

x=+3

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