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7x+5x+6=2(3+6x)
We move all terms to the left:
7x+5x+6-(2(3+6x))=0
We add all the numbers together, and all the variables
7x+5x-(2(6x+3))+6=0
We add all the numbers together, and all the variables
12x-(2(6x+3))+6=0
We calculate terms in parentheses: -(2(6x+3)), so:We get rid of parentheses
2(6x+3)
We multiply parentheses
12x+6
Back to the equation:
-(12x+6)
12x-12x-6+6=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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