2(3z+4)-5=17

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Solution for 2(3z+4)-5=17 equation: 



2(3z+4)-5=17

We move all terms to the left:

2(3z+4)-5-(17)=0

We add all the numbers together, and all the variables

2(3z+4)-22=0

We multiply parentheses

6z+8-22=0

We add all the numbers together, and all the variables

6z-14=0

We move all terms containing z to the left, all other terms to the right

6z=14

z=14/6

z=2+1/3

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