2(3y-5)=32

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Solution for 2(3y-5)=32 equation: 



2(3y-5)=32

We move all terms to the left:

2(3y-5)-(32)=0

We multiply parentheses

6y-10-32=0

We add all the numbers together, and all the variables

6y-42=0

We move all terms containing y to the left, all other terms to the right

6y=42

y=42/6

y=7

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