(7x-2)/5=(-8x-4)/2

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Solution for (7x-2)/5=(-8x-4)/2 equation: 



(7x-2)/5=(-8x-4)/2

We move all terms to the left:

(7x-2)/5-((-8x-4)/2)=0

We calculate fractions


7x/()+(-((-8x-4)*5)/()=0



We calculate terms in parentheses: +(-((-8x-4)*5)/(), so:

-((-8x-4)*5)/(

We multiply all the terms by the denominator


-((-8x-4)*5)



We calculate terms in parentheses: -((-8x-4)*5), so:

(-8x-4)*5

We multiply parentheses

-40x-20

Back to the equation:

-(-40x-20)



We get rid of parentheses

40x+20

Back to the equation:

+(40x+20)



We get rid of parentheses

7x/()+40x+20=0

We multiply all the terms by the denominator


7x+40x*()+20*()=0

We add all the numbers together, and all the variables

7x+40x*()=0

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