2(3y-5)+2=2(y+4)

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Solution for 2(3y-5)+2=2(y+4) equation: 



2(3y-5)+2=2(y+4)

We move all terms to the left:

2(3y-5)+2-(2(y+4))=0

We multiply parentheses

6y-(2(y+4))-10+2=0



We calculate terms in parentheses: -(2(y+4)), so:

2(y+4)

We multiply parentheses

2y+8

Back to the equation:

-(2y+8)



We add all the numbers together, and all the variables

6y-(2y+8)-8=0

We get rid of parentheses

6y-2y-8-8=0

We add all the numbers together, and all the variables

4y-16=0

We move all terms containing y to the left, all other terms to the right

4y=16

y=16/4

y=4

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