2(x-3)=3(x-1)-22

Solution for 2(x-3)=3(x-1)-22 equation:

2(x-3)=3(x-1)-22

We move all terms to the left:

2(x-3)-(3(x-1)-22)=0

We multiply parentheses

2x-(3(x-1)-22)-6=0


We calculate terms in parentheses: -(3(x-1)-22), so:

3(x-1)-22

We multiply parentheses

3x-3-22

We add all the numbers together, and all the variables

3x-25

Back to the equation:

-(3x-25)


We get rid of parentheses

2x-3x+25-6=0

We add all the numbers together, and all the variables

-1x+19=0

We move all terms containing x to the left, all other terms to the right

-x=-19

x=-19/-1

x=+19