2(3y-4)=5y+7

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Solution for 2(3y-4)=5y+7 equation: 



2(3y-4)=5y+7

We move all terms to the left:

2(3y-4)-(5y+7)=0

We multiply parentheses

6y-(5y+7)-8=0

We get rid of parentheses

6y-5y-7-8=0

We add all the numbers together, and all the variables

y-15=0

We move all terms containing y to the left, all other terms to the right

y=15

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