y/2(3y-4)=5y+7

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Solution for y/2(3y-4)=5y+7 equation: 



y/2(3y-4)=5y+7

We move all terms to the left:

y/2(3y-4)-(5y+7)=0



Domain of the equation: 2(3y-4)!=0

y∈R



We get rid of parentheses

y/2(3y-4)-5y-7=0

We multiply all the terms by the denominator


y-5y*2(3y-4)-7*2(3y-4)=0

Wy multiply elements

-10y^2(3-14y(3+y=0

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