2(3y-4)=3(4y+1)

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Solution for 2(3y-4)=3(4y+1) equation: 



2(3y-4)=3(4y+1)

We move all terms to the left:

2(3y-4)-(3(4y+1))=0

We multiply parentheses

6y-(3(4y+1))-8=0



We calculate terms in parentheses: -(3(4y+1)), so:

3(4y+1)

We multiply parentheses

12y+3

Back to the equation:

-(12y+3)



We get rid of parentheses

6y-12y-3-8=0

We add all the numbers together, and all the variables

-6y-11=0

We move all terms containing y to the left, all other terms to the right

-6y=11

y=11/-6

y=-1+5/6

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