2(4-2n)=5(n-2)

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Solution for 2(4-2n)=5(n-2) equation: 



2(4-2n)=5(n-2)

We move all terms to the left:

2(4-2n)-(5(n-2))=0

We add all the numbers together, and all the variables

2(-2n+4)-(5(n-2))=0

We multiply parentheses

-4n-(5(n-2))+8=0



We calculate terms in parentheses: -(5(n-2)), so:

5(n-2)

We multiply parentheses

5n-10

Back to the equation:

-(5n-10)



We get rid of parentheses

-4n-5n+10+8=0

We add all the numbers together, and all the variables

-9n+18=0

We move all terms containing n to the left, all other terms to the right

-9n=-18

n=-18/-9

n=+2

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