2(3y-3)-y+2=2(2y+4)+y-3

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Solution for 2(3y-3)-y+2=2(2y+4)+y-3 equation: 



2(3y-3)-y+2=2(2y+4)+y-3

We move all terms to the left:

2(3y-3)-y+2-(2(2y+4)+y-3)=0

We add all the numbers together, and all the variables

-1y+2(3y-3)-(2(2y+4)+y-3)+2=0

We multiply parentheses

-1y+6y-(2(2y+4)+y-3)-6+2=0



We calculate terms in parentheses: -(2(2y+4)+y-3), so:

2(2y+4)+y-3

We add all the numbers together, and all the variables

y+2(2y+4)-3

We multiply parentheses

y+4y+8-3

We add all the numbers together, and all the variables

5y+5

Back to the equation:

-(5y+5)



We add all the numbers together, and all the variables

5y-(5y+5)-4=0

We get rid of parentheses

5y-5y-5-4=0

We add all the numbers together, and all the variables

-9!=0

There is no solution for this equation

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