2(3y-2)=8(2y-3)

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Solution for 2(3y-2)=8(2y-3) equation: 



2(3y-2)=8(2y-3)

We move all terms to the left:

2(3y-2)-(8(2y-3))=0

We multiply parentheses

6y-(8(2y-3))-4=0



We calculate terms in parentheses: -(8(2y-3)), so:

8(2y-3)

We multiply parentheses

16y-24

Back to the equation:

-(16y-24)



We get rid of parentheses

6y-16y+24-4=0

We add all the numbers together, and all the variables

-10y+20=0

We move all terms containing y to the left, all other terms to the right

-10y=-20

y=-20/-10

y=+2

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