8-2(x+1)=5(x+1)+4

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Solution for 8-2(x+1)=5(x+1)+4 equation: 



8-2(x+1)=5(x+1)+4

We move all terms to the left:

8-2(x+1)-(5(x+1)+4)=0

We multiply parentheses

-2x-(5(x+1)+4)-2+8=0



We calculate terms in parentheses: -(5(x+1)+4), so:

5(x+1)+4

We multiply parentheses

5x+5+4

We add all the numbers together, and all the variables

5x+9

Back to the equation:

-(5x+9)



We add all the numbers together, and all the variables

-2x-(5x+9)+6=0

We get rid of parentheses

-2x-5x-9+6=0

We add all the numbers together, and all the variables

-7x-3=0

We move all terms containing x to the left, all other terms to the right

-7x=3

x=3/-7

x=-3/7

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