2(3y-1)+4y=28*

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Solution for 2(3y-1)+4y=28* equation: 



2(3y-1)+4y=28*

We move all terms to the left:

2(3y-1)+4y-(28*)=0

We add all the numbers together, and all the variables

2(3y-1)+4y-0=0

We add all the numbers together, and all the variables

4y+2(3y-1)=0

We multiply parentheses

4y+6y-2=0

We add all the numbers together, and all the variables

10y-2=0

We move all terms containing y to the left, all other terms to the right

10y=2

y=2/10

y=1/5

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