(2y-3)=3(y+6)

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Solution for (2y-3)=3(y+6) equation: 



(2y-3)=3(y+6)

We move all terms to the left:

(2y-3)-(3(y+6))=0

We get rid of parentheses

2y-(3(y+6))-3=0



We calculate terms in parentheses: -(3(y+6)), so:

3(y+6)

We multiply parentheses

3y+18

Back to the equation:

-(3y+18)



We get rid of parentheses

2y-3y-18-3=0

We add all the numbers together, and all the variables

-1y-21=0

We move all terms containing y to the left, all other terms to the right

-y=21

y=21/-1

y=-21

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