2(3y+4)=5(y+43)

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Solution for 2(3y+4)=5(y+43) equation: 



2(3y+4)=5(y+43)

We move all terms to the left:

2(3y+4)-(5(y+43))=0

We multiply parentheses

6y-(5(y+43))+8=0



We calculate terms in parentheses: -(5(y+43)), so:

5(y+43)

We multiply parentheses

5y+215

Back to the equation:

-(5y+215)



We get rid of parentheses

6y-5y-215+8=0

We add all the numbers together, and all the variables

y-207=0

We move all terms containing y to the left, all other terms to the right

y=207

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