2(3y+3)-4(5y-3)=y(y-3)-y(y+5)

Solution for 2(3y+3)-4(5y-3)=y(y-3)-y(y+5) equation:

2(3y+3)-4(5y-3)=y(y-3)-y(y+5)

We move all terms to the left:

2(3y+3)-4(5y-3)-(y(y-3)-y(y+5))=0

We multiply parentheses

6y-20y-(y(y-3)-y(y+5))+6+12=0


We calculate terms in parentheses: -(y(y-3)-y(y+5)), so:

y(y-3)-y(y+5)

We multiply parentheses

y^2-y^2-3y-5y

We add all the numbers together, and all the variables

-8y

Back to the equation:

-(-8y)


We add all the numbers together, and all the variables

-14y-(-8y)+18=0

We get rid of parentheses

-14y+8y+18=0

We add all the numbers together, and all the variables

-6y+18=0

We move all terms containing y to the left, all other terms to the right

-6y=-18

y=-18/-6

y=+3