(2x+5)/3=(x-7)/2

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Solution for (2x+5)/3=(x-7)/2 equation: 



(2x+5)/3=(x-7)/2

We move all terms to the left:

(2x+5)/3-((x-7)/2)=0

We calculate fractions


2x/()+(-((x-7)*3)/()=0



We calculate terms in parentheses: +(-((x-7)*3)/(), so:

-((x-7)*3)/(

We multiply all the terms by the denominator


-((x-7)*3)



We calculate terms in parentheses: -((x-7)*3), so:

(x-7)*3

We multiply parentheses

3x-21

Back to the equation:

-(3x-21)



We get rid of parentheses

-3x+21

Back to the equation:

+(-3x+21)



We get rid of parentheses

2x/()-3x+21=0

We multiply all the terms by the denominator


2x-3x*()+21*()=0

We add all the numbers together, and all the variables

2x-3x*()=0

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