2(3y+1)=6y+2

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Solution for 2(3y+1)=6y+2 equation: 



2(3y+1)=6y+2

We move all terms to the left:

2(3y+1)-(6y+2)=0

We multiply parentheses

6y-(6y+2)+2=0

We get rid of parentheses

6y-6y-2+2=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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