-2(4-2x)+3x=2x(5+x)-6

Solution for -2(4-2x)+3x=2x(5+x)-6 equation:

-2(4-2x)+3x=2x(5+x)-6

We move all terms to the left:

-2(4-2x)+3x-(2x(5+x)-6)=0

We add all the numbers together, and all the variables

-2(-2x+4)+3x-(2x(x+5)-6)=0

We add all the numbers together, and all the variables

3x-2(-2x+4)-(2x(x+5)-6)=0

We multiply parentheses

3x+4x-(2x(x+5)-6)-8=0


We calculate terms in parentheses: -(2x(x+5)-6), so:

2x(x+5)-6

We multiply parentheses

2x^2+10x-6

Back to the equation:

-(2x^2+10x-6)


We add all the numbers together, and all the variables

7x-(2x^2+10x-6)-8=0

We get rid of parentheses

-2x^2+7x-10x+6-8=0

We add all the numbers together, and all the variables

-2x^2-3x-2=0

a = -2; b = -3; c = -2;
Δ = b2-4ac
Δ = -32-4·(-2)·(-2)
Δ = -7
Delta is less than zero, so there is no solution for the equation