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2(3x/15)=6(x-5)
We move all terms to the left:
2(3x/15)-(6(x-5))=0
We add all the numbers together, and all the variables
2(+3x/15)-(6(x-5))=0
We multiply parentheses
6x-(6(x-5))=0
We calculate terms in parentheses: -(6(x-5)), so:We get rid of parentheses
6(x-5)
We multiply parentheses
6x-30
Back to the equation:
-(6x-30)
6x-6x+30=0
We add all the numbers together, and all the variables
30!=0
There is no solution for this equation
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