2(3x-8)=3(4x)+6x

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Solution for 2(3x-8)=3(4x)+6x equation: 



2(3x-8)=3(4x)+6x

We move all terms to the left:

2(3x-8)-(3(4x)+6x)=0

We add all the numbers together, and all the variables

2(3x-8)-(+40x)=0

We multiply parentheses

6x-(+40x)-16=0

We get rid of parentheses

6x-40x-16=0

We add all the numbers together, and all the variables

-34x-16=0

We move all terms containing x to the left, all other terms to the right

-34x=16

x=16/-34

x=-8/17

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