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(x-5)(300+5x)=300x
We move all terms to the left:
(x-5)(300+5x)-(300x)=0
We add all the numbers together, and all the variables
(x-5)(5x+300)-300x=0
We add all the numbers together, and all the variables
-300x+(x-5)(5x+300)=0
We multiply parentheses ..
(+5x^2+300x-25x-1500)-300x=0
We get rid of parentheses
5x^2+300x-25x-300x-1500=0
We add all the numbers together, and all the variables
5x^2-25x-1500=0
a = 5; b = -25; c = -1500;
Δ = b2-4ac
Δ = -252-4·5·(-1500)
Δ = 30625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{30625}=175$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-175}{2*5}=\frac{-150}{10} =-15 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+175}{2*5}=\frac{200}{10} =20 $
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