2(3x-6)=3(x+20)

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Solution for 2(3x-6)=3(x+20) equation: 



2(3x-6)=3(x+20)

We move all terms to the left:

2(3x-6)-(3(x+20))=0

We multiply parentheses

6x-(3(x+20))-12=0



We calculate terms in parentheses: -(3(x+20)), so:

3(x+20)

We multiply parentheses

3x+60

Back to the equation:

-(3x+60)



We get rid of parentheses

6x-3x-60-12=0

We add all the numbers together, and all the variables

3x-72=0

We move all terms containing x to the left, all other terms to the right

3x=72

x=72/3

x=24

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