3x+4(3x-5)=12-x

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Solution for 3x+4(3x-5)=12-x equation: 



3x+4(3x-5)=12-x

We move all terms to the left:

3x+4(3x-5)-(12-x)=0

We add all the numbers together, and all the variables

3x+4(3x-5)-(-1x+12)=0

We multiply parentheses

3x+12x-(-1x+12)-20=0

We get rid of parentheses

3x+12x+1x-12-20=0

We add all the numbers together, and all the variables

16x-32=0

We move all terms containing x to the left, all other terms to the right

16x=32

x=32/16

x=2

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