2(3x-6)-4x+20=-6(x-3)+7

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Solution for 2(3x-6)-4x+20=-6(x-3)+7 equation: 



2(3x-6)-4x+20=-6(x-3)+7

We move all terms to the left:

2(3x-6)-4x+20-(-6(x-3)+7)=0

We add all the numbers together, and all the variables

-4x+2(3x-6)-(-6(x-3)+7)+20=0

We multiply parentheses

-4x+6x-(-6(x-3)+7)-12+20=0



We calculate terms in parentheses: -(-6(x-3)+7), so:

-6(x-3)+7

We multiply parentheses

-6x+18+7

We add all the numbers together, and all the variables

-6x+25

Back to the equation:

-(-6x+25)



We add all the numbers together, and all the variables

2x-(-6x+25)+8=0

We get rid of parentheses

2x+6x-25+8=0

We add all the numbers together, and all the variables

8x-17=0

We move all terms containing x to the left, all other terms to the right

8x=17

x=17/8

x=2+1/8

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