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(2x+4)+1x=(3x+13)
We move all terms to the left:
(2x+4)+1x-((3x+13))=0
We add all the numbers together, and all the variables
x+(2x+4)-((3x+13))=0
We get rid of parentheses
x+2x-((3x+13))+4=0
We calculate terms in parentheses: -((3x+13)), so:We add all the numbers together, and all the variables
(3x+13)
We get rid of parentheses
3x+13
Back to the equation:
-(3x+13)
3x-(3x+13)+4=0
We get rid of parentheses
3x-3x-13+4=0
We add all the numbers together, and all the variables
-9!=0
There is no solution for this equation
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