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2(3x-5)=7(3x+5)
We move all terms to the left:
2(3x-5)-(7(3x+5))=0
We multiply parentheses
6x-(7(3x+5))-10=0
We calculate terms in parentheses: -(7(3x+5)), so:We get rid of parentheses
7(3x+5)
We multiply parentheses
21x+35
Back to the equation:
-(21x+35)
6x-21x-35-10=0
We add all the numbers together, and all the variables
-15x-45=0
We move all terms containing x to the left, all other terms to the right
-15x=45
x=45/-15
x=-3
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