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2(3x-5)=-3-3(x+4)
We move all terms to the left:
2(3x-5)-(-3-3(x+4))=0
We multiply parentheses
6x-(-3-3(x+4))-10=0
We calculate terms in parentheses: -(-3-3(x+4)), so:We get rid of parentheses
-3-3(x+4)
determiningTheFunctionDomain -3(x+4)-3
We multiply parentheses
-3x-12-3
We add all the numbers together, and all the variables
-3x-15
Back to the equation:
-(-3x-15)
6x+3x+15-10=0
We add all the numbers together, and all the variables
9x+5=0
We move all terms containing x to the left, all other terms to the right
9x=-5
x=-5/9
x=-5/9
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