X2+136x=16

Solution for X2+136x=16 equation:

X2+136X=16

We move all terms to the left:

X2+136X-(16)=0

We add all the numbers together, and all the variables

X^2+136X-16=0

a = 1; b = 136; c = -16;
Δ = b2-4ac
Δ = 1362-4·1·(-16)
Δ = 18560
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{18560}=\sqrt{64*290}=\sqrt{64}*\sqrt{290}=8\sqrt{290}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(136)-8\sqrt{290}}{2*1}=\frac{-136-8\sqrt{290}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(136)+8\sqrt{290}}{2*1}=\frac{-136+8\sqrt{290}}{2}
$