2(3x-5)=-(8x+1)+8

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Solution for 2(3x-5)=-(8x+1)+8 equation: 



2(3x-5)=-(8x+1)+8

We move all terms to the left:

2(3x-5)-(-(8x+1)+8)=0

We multiply parentheses

6x-(-(8x+1)+8)-10=0



We calculate terms in parentheses: -(-(8x+1)+8), so:

-(8x+1)+8

We get rid of parentheses

-8x-1+8

We add all the numbers together, and all the variables

-8x+7

Back to the equation:

-(-8x+7)



We get rid of parentheses

6x+8x-7-10=0

We add all the numbers together, and all the variables

14x-17=0

We move all terms containing x to the left, all other terms to the right

14x=17

x=17/14

x=1+3/14

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