6(2y+12)+4y=8(y+9)

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Solution for 6(2y+12)+4y=8(y+9) equation: 



6(2y+12)+4y=8(y+9)

We move all terms to the left:

6(2y+12)+4y-(8(y+9))=0

We add all the numbers together, and all the variables

4y+6(2y+12)-(8(y+9))=0

We multiply parentheses

4y+12y-(8(y+9))+72=0



We calculate terms in parentheses: -(8(y+9)), so:

8(y+9)

We multiply parentheses

8y+72

Back to the equation:

-(8y+72)



We add all the numbers together, and all the variables

16y-(8y+72)+72=0

We get rid of parentheses

16y-8y-72+72=0

We add all the numbers together, and all the variables

8y=0

y=0/8

y=0

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