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2(3x-5)-3=2(x-4)+3
We move all terms to the left:
2(3x-5)-3-(2(x-4)+3)=0
We multiply parentheses
6x-(2(x-4)+3)-10-3=0
We calculate terms in parentheses: -(2(x-4)+3), so:We add all the numbers together, and all the variables
2(x-4)+3
We multiply parentheses
2x-8+3
We add all the numbers together, and all the variables
2x-5
Back to the equation:
-(2x-5)
6x-(2x-5)-13=0
We get rid of parentheses
6x-2x+5-13=0
We add all the numbers together, and all the variables
4x-8=0
We move all terms containing x to the left, all other terms to the right
4x=8
x=8/4
x=2
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