16(x-3)(x+6)=0

Solution for 16(x-3)(x+6)=0 equation:

16(x-3)(x+6)=0

We multiply parentheses ..

16(+x^2+6x-3x-18)=0

We multiply parentheses

16x^2+96x-48x-288=0

We add all the numbers together, and all the variables

16x^2+48x-288=0

a = 16; b = 48; c = -288;
Δ = b2-4ac
Δ = 482-4·16·(-288)
Δ = 20736
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{20736}=144$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-144}{2*16}=\frac{-192}{32}
=-6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+144}{2*16}=\frac{96}{32}
=3
$