23-7(x+3)5x=10+

Solution for 23-7(x+3)5x=10+ equation:

23-7(x+3)5x=10+

We move all terms to the left:

23-7(x+3)5x-(10+)=0

We add all the numbers together, and all the variables

-7(x+3)5x+23-0=0

We add all the numbers together, and all the variables

-7(x+3)5x+23=0

We multiply parentheses

-35x^2-105x+23=0

a = -35; b = -105; c = +23;
Δ = b2-4ac
Δ = -1052-4·(-35)·23
Δ = 14245
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-105)-\sqrt{14245}}{2*-35}=\frac{105-\sqrt{14245}}{-70}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-105)+\sqrt{14245}}{2*-35}=\frac{105+\sqrt{14245}}{-70}
$