2(3x-5)+3(2x+6)=32

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Solution for 2(3x-5)+3(2x+6)=32 equation: 



2(3x-5)+3(2x+6)=32

We move all terms to the left:

2(3x-5)+3(2x+6)-(32)=0

We multiply parentheses

6x+6x-10+18-32=0

We add all the numbers together, and all the variables

12x-24=0

We move all terms containing x to the left, all other terms to the right

12x=24

x=24/12

x=2

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