3x-2(4x-3)=7(x+6)

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Solution for 3x-2(4x-3)=7(x+6) equation: 



3x-2(4x-3)=7(x+6)

We move all terms to the left:

3x-2(4x-3)-(7(x+6))=0

We multiply parentheses

3x-8x-(7(x+6))+6=0



We calculate terms in parentheses: -(7(x+6)), so:

7(x+6)

We multiply parentheses

7x+42

Back to the equation:

-(7x+42)



We add all the numbers together, and all the variables

-5x-(7x+42)+6=0

We get rid of parentheses

-5x-7x-42+6=0

We add all the numbers together, and all the variables

-12x-36=0

We move all terms containing x to the left, all other terms to the right

-12x=36

x=36/-12

x=-3

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