2(3x-4)=4x+32x

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Solution for 2(3x-4)=4x+32x equation: 



2(3x-4)=4x+32x

We move all terms to the left:

2(3x-4)-(4x+32x)=0

We add all the numbers together, and all the variables

2(3x-4)-(+36x)=0

We multiply parentheses

6x-(+36x)-8=0

We get rid of parentheses

6x-36x-8=0

We add all the numbers together, and all the variables

-30x-8=0

We move all terms containing x to the left, all other terms to the right

-30x=8

x=8/-30

x=-4/15

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