((x-40)/2)+((x-40)/3)=0

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Solution for ((x-40)/2)+((x-40)/3)=0 equation: 



((x-40)/2)+((x-40)/3)=0

We calculate fractions


(3x-120)/()+(2x-80)/()=0

We multiply all the terms by the denominator


(3x-120)+(2x-80)=0

We get rid of parentheses

3x+2x-120-80=0

We add all the numbers together, and all the variables

5x-200=0

We move all terms containing x to the left, all other terms to the right

5x=200

x=200/5

x=40

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