# 2(3x-4)=4(1/8x-8)

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## Solution for 2(3x-4)=4(1/8x-8) equation:

2(3x-4)=4(1/8x-8)
We move all terms to the left:
2(3x-4)-(4(1/8x-8))=0

Domain of the equation: 8x-8))!=0
x∈R

We multiply parentheses
6x-(4(1/8x-8))-8=0
We multiply all the terms by the denominator

6x*8x-8*8x-8))-(4(1-8))=0
We add all the numbers together, and all the variables
6x*8x-8*8x-8))-(4(-7))=0
We add all the numbers together, and all the variables
6x*8x-8*8x=0
Wy multiply elements
48x^2-64x=0
a = 48; b = -64; c = 0;Δ = b2-4acΔ = -642-4·48·0Δ = 4096The delta value is higher than zero, so the equation has two solutionsWe use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4096}=64$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-64)-64}{2*48}=\frac{0}{96} =0$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-64)+64}{2*48}=\frac{128}{96} =1+1/3$

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