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2x-4(x-3)=-9+3x+11
We move all terms to the left:
2x-4(x-3)-(-9+3x+11)=0
We add all the numbers together, and all the variables
2x-4(x-3)-(3x+2)=0
We multiply parentheses
2x-4x-(3x+2)+12=0
We get rid of parentheses
2x-4x-3x-2+12=0
We add all the numbers together, and all the variables
-5x+10=0
We move all terms containing x to the left, all other terms to the right
-5x=-10
x=-10/-5
x=+2
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