2(3x-4)-22=-3(x-2)

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Solution for 2(3x-4)-22=-3(x-2) equation: 



2(3x-4)-22=-3(x-2)

We move all terms to the left:

2(3x-4)-22-(-3(x-2))=0

We multiply parentheses

6x-(-3(x-2))-8-22=0



We calculate terms in parentheses: -(-3(x-2)), so:

-3(x-2)

We multiply parentheses

-3x+6

Back to the equation:

-(-3x+6)



We add all the numbers together, and all the variables

6x-(-3x+6)-30=0

We get rid of parentheses

6x+3x-6-30=0

We add all the numbers together, and all the variables

9x-36=0

We move all terms containing x to the left, all other terms to the right

9x=36

x=36/9

x=4

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