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3(2x+1)+5=2(3x+4)
We move all terms to the left:
3(2x+1)+5-(2(3x+4))=0
We multiply parentheses
6x-(2(3x+4))+3+5=0
We calculate terms in parentheses: -(2(3x+4)), so:We add all the numbers together, and all the variables
2(3x+4)
We multiply parentheses
6x+8
Back to the equation:
-(6x+8)
6x-(6x+8)+8=0
We get rid of parentheses
6x-6x-8+8=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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