2(3x-4)+5=3+2(2x+3)-8

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Solution for 2(3x-4)+5=3+2(2x+3)-8 equation: 



2(3x-4)+5=3+2(2x+3)-8

We move all terms to the left:

2(3x-4)+5-(3+2(2x+3)-8)=0

We multiply parentheses

6x-(3+2(2x+3)-8)-8+5=0



We calculate terms in parentheses: -(3+2(2x+3)-8), so:

3+2(2x+3)-8

determiningTheFunctionDomain
2(2x+3)+3-8

We add all the numbers together, and all the variables

2(2x+3)-5

We multiply parentheses

4x+6-5

We add all the numbers together, and all the variables

4x+1

Back to the equation:

-(4x+1)



We add all the numbers together, and all the variables

6x-(4x+1)-3=0

We get rid of parentheses

6x-4x-1-3=0

We add all the numbers together, and all the variables

2x-4=0

We move all terms containing x to the left, all other terms to the right

2x=4

x=4/2

x=2

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